dy/dx=sin(x+y)+cos(x+y)

Dear upendra

dy/dx=sin(x+y)+cos(x+y)

let   x+y=u

1+dy/dx=du/dy

so differential become

du/dy -1 =sinu  +cosu

du/dy=sinu +cosu +1

du/(sinu +cosu +1)   =dy

∫du/(sinu +cosu +1) =∫dy

now this a ordinary intigral u can easly solve it

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