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dy/dx=sin(x+y)+cos(x+y)

dy/dx=sin(x+y)+cos(x+y)

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear upendra

dy/dx=sin(x+y)+cos(x+y)

let   x+y=u

1+dy/dx=du/dy

so differential become

du/dy -1 =sinu  +cosu

du/dy=sinu +cosu +1

du/(sinu +cosu +1)   =dy

du/(sinu +cosu +1) =∫dy

now this a ordinary intigral u can easly solve it


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