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y=f(a^x) and f(sinx)=lnx find dy/dx

y=f(a^x)   and f(sinx)=lnx    find dy/dx

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2 Answers

Rajendra Sharma
20 Points
8 years ago

dy/dx = (a^x)(lnx)f''(a^x), .........(1)

but f(sinx) = lnx implies f(x) = ln(arcsinx)

hence f''(x) = (1/arcsinx) (1/ ( ( 1-x^2 ) ^ ( !/2 ) ) implies f''(a^x) = (1/arcsin(a^x)) (1/ ((1-a ^ (2x)) ^ (1/2))) ............(2)

hence from ...(1) &.....(2) the solution is obtained but it should br noted that the given solution exist only when x belongs to (0,1].

Rajendra Sharma
20 Points
8 years ago

dy/dx exist only when 0<a<1 and is equal to the given solution while dy/dx does not exist when a>1 as the function y = f(a^x) itself does not exist.

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