Differentiate Sin^2 x with respect to e^ cosx

Dear Aswathi

 we know that dy/dz can be written as

                 dy/dz = (dy/dx) / (dz/dx)

So here, y=sin^2x & z = e^cosx

  so dy/dx = 2 sinx cosx           &          dz/dx = -sinx (e^cosx)

Thus , your answer is

             (dy/dx) / (dz/dx) = - (2cosx / e^cosx)

:)  Hit like if u like the answer :)

I think answer is

=2*(sin x)*e^(-cos x)