Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Differentiate Sin^2 x with respect to e^ cosx

Differentiate Sin^2 x with respect to e^ cosx

Grade:

3 Answers

Sajin SS
36 Points
8 years ago

Dear Aswathi

 we know that dy/dz can be written as

                 dy/dz = (dy/dx) / (dz/dx)

So here, y=sin^2x & z = e^cosx

  so dy/dx = 2 sinx cosx           &          dz/dx = -sinx (e^cosx)

Thus , your answer is

             (dy/dx) / (dz/dx) = - (2cosx / e^cosx)

:)  Hit like if u like the answer :)

Harshal Sureshbhai Davda
33 Points
8 years ago

I think answer is

=2*(sin x)*e^(-cos x)

Kushagra Madhukar
askIITians Faculty 629 Points
10 months ago
Dear student,
Please find the solution to your question.
 
Let, y = sin2x and z = ecosx
dy/dx = 2sinx.cosx  ;    dz/dx = ecosx.( – sinx)
Now, dy/dz = (dy/dx).(dx/dz) = (dy/dx)/(dz/dx)
= 2sinxcosx/( – ecosxsinx)
= – 2cosx.e–cosx
 
Thanks and regads,
Kushagra

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free