Differentiate Sin^2 x with respect to e^ cosx
Dear Aswathi
we know that dy/dz can be written as
dy/dz = (dy/dx) / (dz/dx)
So here, y=sin^2x & z = e^cosx
so dy/dx = 2 sinx cosx & dz/dx = -sinx (e^cosx)
Thus , your answer is
(dy/dx) / (dz/dx) = - (2cosx / e^cosx)
:) Hit like if u like the answer :)
I think answer is
=2*(sin x)*e^(-cos x)
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Last Activity: 3 Years ago