Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Fint the shortest distance of the point (0,c) from the parobola y=x 2 where 0≤c≤5. ANSWER-½√(4c-1)

Fint the shortest distance of the point (0,c) from the parobola y=x2 where 0≤c≤5.  ANSWER-½√(4c-1)

Grade:12

1 Answers

Swapnil Saxena
102 Points
9 years ago

Let there be a point on the parabola (x,y) which is closest to the given point.

Then the distance this point from (x,y)= √(x-0)2 + (y-c)2 .Substituting the value of x2 with y the  equation becomes √y + (y-c)2=√y + y2+c2-2yc Differentiating the equ with respect to y

We get (1+2y-2c)/(2(√y + y2+c2-2yc))=0 ==> y=(2c-1)/2=c-(1/2)

Then x=√c-(1/2). The distance of the point =√(c-(1/2) + (c-(1/2)-c)2)=√c-(1/2) + (1/4) =√c-(1/4)=½√(4c-1)

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free