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```
If ƒ(x)=[cosx cos(x+2)-cos 2 (x+1)],where[.] denotes the greatest integer function≤x.Then solution of the equation ƒ(x)=x is

```
11 years ago

```							hi,
[cos(x) cos(x+2) - cos^2(x+1)] = x
expending above eqn & solving we get
[(cos^2x)(cos2)-(cos^2x)cos^2(1) - sin^2(1) + cos^2x sin^2(1)] = x
[(cos^2x){cos2 - cos^2(1) + sin^2(1)} - sin^2(1)] = x
[(cos^2x){(2cos^2(1)-1) - cos^2(1) + (1-cos^2(1)} -sin^2(1)] = x
[cos^x * 0 - sin^2(1)] = -1 = x
becoz [-sin^2(1)] = -1
so, ans. is x = -1

```
11 years ago
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