0

Guest

Courses New

If ƒ(x)=[cosx cos(x+2)-cos 2 (x+1)],where[.] denotes the greatest integer function≤x.Then solution of the equation ƒ(x)=x is

If ƒ(x)=[cosx cos(x+2)-cos2(x+1)],where[.] denotes the greatest integer function≤x.Then solution of the equation        ƒ(x)=x  is

Grade:12

1 Answers

anandpal shekhawat
8 Points
14 years ago
hi, [cos(x) cos(x+2) - cos^2(x+1)] = x expending above eqn & solving we get [(cos^2x)(cos2)-(cos^2x)cos^2(1) - sin^2(1) + cos^2x sin^2(1)] = x [(cos^2x){cos2 - cos^2(1) + sin^2(1)} - sin^2(1)] = x [(cos^2x){(2cos^2(1)-1) - cos^2(1) + (1-cos^2(1)} -sin^2(1)] = x [cos^x * 0 - sin^2(1)] = -1 = x becoz [-sin^2(1)] = -1 so, ans. is x = -1

Think You Can Provide A Better Answer ?

Other Related Questions on Differential Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More