Ashwin Muralidharan IIT Madras
Last Activity: 13 Years ago
Hi Basit,
Use the property [x] = x - {x}
You will get
a+2a+3a+......na - ({a}+{2a}+.....{na})
ie a*n*(n+1)/2 - ({a}+{2a}+...{na})
as limit n tends to infinity, first term will tend to a/2, and then term in the brackets will tend to n (which is divided by n^2) and hence will tend to 0.
So answer is a/2.
Regards,
Ashwin (IIT Madras).