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f(x)=root(log0.3(x-1)/x2-2x-8)
The domain of f(x) is : necessary condition : (x-1)>0 the value under f(x) shld always be positive case 1: log0.3(x-1) > 0 and (x+2)(x-4) > 0 x-1 > 1 and (x+2)(x-4) > 0 and x>1 the overlapping region is x > 4 case 1: log0.3(x-1) < 0 and (x+2)(x-4) < 0 x-1 < 1 and (x+2)(x-4) < 0 x<2 and -2<x<4 and x>1 the overlapping region is : (1 , 2) the domain is : (1,2) U (4,infinity) -- Regards Ramesh
The domain of f(x) is :
necessary condition : (x-1)>0
the value under f(x) shld always be positive
case 1:
log0.3(x-1) > 0 and (x+2)(x-4) > 0
x-1 > 1 and (x+2)(x-4) > 0 and x>1
the overlapping region is x > 4
log0.3(x-1) < 0 and (x+2)(x-4) < 0
x-1 < 1 and (x+2)(x-4) < 0
x<2 and -2<x<4 and x>1
the overlapping region is : (1 , 2)
the domain is : (1,2) U (4,infinity)
--
Regards
Ramesh
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