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Grade: 12
        

If the normal to the curve y=f (x) at the point (3, 4) makes an angle 3 p/4 with the positive x-axis then f' (3) =
(A) –1                                      (B) –3/4
(C) 4/3                                

10 years ago

Answers : (2)

AskIITian Expert Priyasheel - IITD
8 Points
							

y =f(x)

Slope of the normal at (x,y) to the curve = -1/f'(x)

Given, -1/f'(x) = tan (3pi/4) =-1,

So, f'(3)=1.

10 years ago
Sudheesh Singanamalla
114 Points
							

Slope of normal to y = f(x) at (3,4) is -1/f'(3). Thus

-1 / f'(3) = tan (3∏ / 4 ) = tan(∏/2 + ∏/4) = -cot(∏/4) = -1

=> f'(3) = 1

 

Hope that helps :)

9 years ago
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