Guest

ydx + x[logy/x]dy - 2xdy=0 solve using variable separable method

ydx + x[logy/x]dy - 2xdy=0 solve using variable separable method

Grade:11

1 Answers

bharat bajaj IIT Delhi
askIITians Faculty 122 Points
8 years ago
ydx + x[logy/x]dy - 2xdy=0
ydx -xdy +x[logy/x]dy -xdy = 0
divide by x^2
(ydx-xdy)/x^2 + (logy/x - 1)/x^2 . dy = 0
-d(y/x) +(logy/x-1)(y/x)^2 / y^2 .dy = 0
Take y/x=z
dz - (logz-1)z^2/y^2 dy = 0
dz(z^2)(logz-1) = dy/y^2
Now integrate it as the variables are separated and put z = y/x at the end.
Thanks
bharat Bajaj
IIT Delhi
askiitians faculty

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free