Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
third term of an ap is p and fourth term is q then the 10 tern is
Dear studentA3 = p = a + 2da is first term d is common differenced = (q-p)A4 = a + 3d = qa= 3p-2qA10 = a + 9d(3p-2q) +(q-p)9= 7q -6p
Given t3 = p and t4 = qnth term or general term of AP is tn = a + (n – 1)d⇒ t3 = a + 2d = p → (1)⇒ t4 = a + 3d = q → (2)Subtract (1) from (2), we getd = q – pPut value of d in (1), we geta + 2(q – p) = p⇒ a = p – 2q + 2p = 3p – 2qGeneral term, tn = (3p – 2q) + (n – 1)(q – p)= 3p – 2q – q + p + n(q – p)tn = 4p – 3q + n(q – p)Put n = 10 in tnt10 = 4p – 3q + 10(q – p) = 4p – 3q + 10q – 10p = 7q – 6p
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -