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The equation of circle with centre (3,2) and the power of (1,-2) w.r.t. the circle x²+y²=1 as radius is.

The equation of circle with centre (3,2) and the power of (1,-2) w.r.t. the circle x²+y²=1 as radius is.

Grade:11

1 Answers

Shukant Pal
25 Points
3 years ago
The power of a point w.r.t a circle is defined as the product of the algebraical distances PA and PB when from P a secant be drawn from the point P to the circle intersecting it at A and B. This value is independent of the slope of the secant and is also equal to the square of the length of tangents drawn from the point on the circle.
 
The power of the point P(h,k) w.r.t the circle x2 + y2 + 2gx + 2fy + c = 0, is h2 + k2 + 2gh + 2fk + c = 0. From this you should be able solve the problem.

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