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Sides of an equilateral triangle ABC touch the parabola y 2 =4ax, then the points A,B and C lie on y 2 =(x+a) 2 +4ax y 2 =3(x+a) 2 + ax y 2 =3(x+a) 2 +4ax d.y 2 =(x+a) 2 +ax

 
Sides of an equilateral triangle ABC touch the parabola y2=4ax, then the points A,B and C lie on
  1. y2=(x+a)2 +4ax
  1. y2=3(x+a)2 + ax
  1. y2=3(x+a)2 +4ax
      d.y2=(x+a)2 +ax

Grade:12

1 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
2 years ago

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