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question mark

Sides of an equilateral triangle ABC touch the parabola y2=4ax, then the points A,B and C lie on
  1. y2=(x+a)2 +4ax
  1. y2=3(x+a)2 + ax
  1. y2=3(x+a)2 +4ax
d.y2=(x+a)2 +ax

Sayam , 9 Years ago
Grade 12
anser 1 Answers
Saurabh Koranglekar
Last Activity: 6 Years ago
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