Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
show that all the chords of the curve 3x²-y²-2x+4y=0 which subtend a right angle at the origin pass through a fixed point
Let (x,y) be a common point of chord y=mx+c, y=kx & 3x²−y²−2x+4y=0First two give x & y which can be used in third to give (3−k²)c + (4k−2)(k−m) = 0As a quadratic in k this is k²(4−c)−2k(2m+1)+(2m+3c) = 0If the two values of k arising from this give perp lines thro O then (2m+3c)/(4−c) = −1→ 2m+3c = −4+c → c=−m−2Chord is thus y = mx–m−2 → y+2 = m(x−1) which always contains (1,−2)
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -