Show that (-1/2,2,0) is the circum centre of the triangle formed by the points(1,2,1),(-2,2,-1),(1,1,0)

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Arun · Answer

Let A = (1,2,1)B = (-2,2,-1)C = (1,1,0) if we find length AB = 13 length BC = 11 length AC = 2 thus we see that AB 2 = BC 2 + AC 2 thus ABC is a right angled triangle with hypotenuse AB. In a right angled triangle circumcentre will be at the middle point of hypotenuse thus in this question circumcentre = mid point of AB circumcentre = [(1–2)/2 ,(2+2)/2 , (1–1)/2 ] = ( –1/2 , 2 , 0 ) hence proved

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Show that (-1/2,2,0) is the circum centre of the triangle formed by the points(1,2,1),(-2,2,-1),(1,1,0)

Show that (-1/2,2,0) is the circum centre of the triangle formed by the points(1,2,1),(-2,2,-1),(1,1,0)

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