if y=m1x+c and y=m2x+c are two tangents to the parabola y^2+4a(x+a)=0then, find the relation between m1 and m2a)m1+m2=0b)1+m1+m2=0c)m1m2-1=0​d)1+m1m2=0please answer with solution

let line y=mx+c is tangent then
(mx+c)²+4ax+4a²=0 here D=0 as it is tangent then
m²x²+2mxc+c²+4ax+4a²=0
D=0
(2mc+4a)²-4(c²+4a²)m²=0
16a²+16amc-16a²m²=0
a+mc=am²
c=a(m²-1)/m replace it again
for both tangents c is same so m1m2 =1