Aditya Gupta
Last Activity: 5 Years ago
note that aruns ans is once again wrong, non sensical and poorly understood.
he doesnt even understand the meaning of supplementary angles.
let triangles be ABC and PQR.
given AB= PQ
AC= PR
and the included angles are supplementary implies that they add up to 180.
so that angle BAC + angle QPR= 180
or angle QPR= 180 – angle BAC
now, we use the following formula for area:
area of ABC= ½ AB*AC*sin(angle BAC) (note that the proof of this formula is easy and can be found online)
and area of PQR= ½ PQ*PR*sin(angle QPR)= ½ AB*AC*sin(180 – angle BAC)= ½ AB*AC*sin(angle BAC).
hence, area of ABC= area of PQR.
KINDLY APPROVE :))