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If teta is the angle between the asymptotes of hyperbola x2/a2-y2/b2 = 1with eccentricity e, then sec teta/ 2=?? ( e,e/2,e/3,e/(e2-1)1/2)

If teta is the angle between the asymptotes of hyperbola x2/a2-y2/b2 = 1with eccentricity e, then sec teta/ 2=?? ( e,e/2,e/3,e/(e2-1)1/2)

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
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