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If (-6,-4) and (3,5) are the extremities of the diagonals of a parallelogram and (2,-1) is its third vertex, then its fourth vertex is
Let P(-6,-4) Q(2,-1) R(3,5) S(x,y)The two diagonals of a parallelogram bisect each other. So the midpoint of PR = midpoint of QS so using that midpoint of PR = (-6+3)/2 , (-4+5)/2 ) =(-3/2,1/2)=>midpoint of QS= (-3/2,1/2) ={(2+x)/2 ,(-1+y)/2}=>s=(-5,2).
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