Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

How to find the equation common tangents of parabola y^2=4x and circle x^2 + y^2 = 1?

How to find the equation common tangents of parabola y^2=4x and circle x^2 + y^2 = 1?

Grade:12

1 Answers

Vikas TU
14149 Points
3 years ago

focal point of circle: (0,0) 
Condition of digression on parabola: 
y=mx+a/m 
a=1 
y=mx+1/m 
Opposite Distance from the focal point of the circle = 0 
|3m+1/m|/(1+m)1/2=3 
m2=1/3 => m=+1/√3 or - 1/√3 
As digression is above x-hub, slant is (+)ve 
In this manner, Equation of digression: 
y=x/√3+√3 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free