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For x,y€R x^2+y^2+xy=1 then the minimum value of x^3y+xy^3+4=0 IS

For x,y€R x^2+y^2+xy=1 then the minimum value of x^3y+xy^3+4=0 IS

Grade:12

1 Answers

Arun
25763 Points
3 years ago
Dear Manu
 
x^3y + xy^3 + 4
xy (x^2 + y^2) +4
 
but 
x^2 + y^2 = 1 – xy
 
hence
xy (1 – xy) + 4
 
xy – x^2y^2 + 4
 
hence minimum value I thnk should be 4

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