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Find the locus of the point of intersection of two perpendicular lines each of which touches one of the two circles (x-a)2+(y)2=b2 ,(x+a)2+(y)2=c2 and prove that the bisectors of the angles between the straight lines always touch one or the other fixed circles.

Raghav Kumar , 10 Years ago
Grade 12th pass
anser 1 Answers
Askiitians Tutor Team

To find the locus of the point of intersection of two perpendicular lines, each tangent to one of the two given circles, we start by analyzing the equations of the circles and the properties of tangents and perpendicular lines. The circles are defined as follows:

Circle Equations

The equations of the circles are:

  • Circle 1: (x - a)² + y² = b²
  • Circle 2: (x + a)² + y² = c²

Here, the first circle is centered at (a, 0) with radius b, and the second circle is centered at (-a, 0) with radius c. The goal is to find the locus of the intersection point of two perpendicular tangents to these circles.

Finding the Tangents

For a circle, the equation of the tangent line at a point (x₁, y₁) on the circle can be derived using the formula:

(x - x₁)(x₁ - h) + (y - y₁)(y₁ - k) = r²

where (h, k) is the center of the circle and r is the radius. For our circles, we can derive the equations of the tangents at points on each circle.

Perpendicular Tangents

Let’s denote the points of tangency on Circle 1 as (x₁, y₁) and on Circle 2 as (x₂, y₂). The lines are perpendicular if the product of their slopes is -1. If we denote the slopes of the tangents as m₁ and m₂, then:

m₁ * m₂ = -1

Finding the Intersection Point

The intersection point of the two tangents can be found by solving the equations of the tangents simultaneously. The coordinates of the intersection point (x, y) will depend on the specific points of tangency chosen on each circle.

Locus of the Intersection Point

To find the locus of the intersection point as the points of tangency vary, we can use the concept of the radical axis. The radical axis of two circles is the locus of points that have equal power with respect to the two circles. The power of a point (x, y) with respect to a circle is given by:

P = (x - h)² + (y - k)² - r²

For our circles, the radical axis can be derived from the equations:

(x - a)² + y² - b² = (x + a)² + y² - c²

Upon simplifying, we find:

-2ax = c² - b² + 2a²

Thus, the locus of the intersection point is a line given by:

x = (c² - b² + 2a²) / (2a)

Angle Bisectors and Their Properties

Now, regarding the angle bisectors of the tangents, we can use the property that the angle bisector of two lines will always touch the circles at points where the tangents meet. The angle bisector theorem states that the angle bisector divides the angle into two equal parts, and thus, it will also maintain the property of tangency to the circles.

Conclusion

In summary, the locus of the point of intersection of two perpendicular tangents to the circles is a line, and the angle bisectors of these tangents will always touch one of the circles. This is due to the geometric properties of circles and tangents, as well as the nature of angle bisectors in relation to the circles they touch.

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