Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Find the equations of the chords of a parabola y^2=4ax which pass through the point (-6a, 0) and subtends an angle of 45° at the vertex.

Find the equations of the chords of a parabola y^2=4ax which pass through the point (-6a, 0) and subtends an angle of 45° at the vertex.

Grade:11

1 Answers

Arun
25763 Points
4 years ago
The vertex of parabola
𝑦
2 = 4𝑎𝑥
is (0,0).
 Equation of a chord in the slope-intercept form is
y=kx+b (1)
Here k=tan 45°=1, because a chord subtends an angle of 45° at the vertex.
So, in fact (1) is given by
y=x+b (2)
On the other hand, this line passes through the point (–6a, 0), consequently its coordinates satisfy equation
(2):
0=-6a+b,
b=6a.
Finally, y=x+6a is the equation of chord.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free