MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
Find the equation to the circle which passes through the points (1,-2)(4,-3) and which has its centre on the straight line 3x+4y=7.  I am not getting the answer.
Answer is 15x²+15y²-94x+18y+55
11 months ago

Answers : (1)

Kushagra dutt
24 Points
							Let the centre of the circle be (h,k)which Satisfy the equation of the line which passes through the the centre i.e. 3h+4k=7...........(eq.1)Now from the two given point (1,-2) and (4,-3) equate the radius by using distance formula and the final equation you get is3h-k=11...............(eq.2)Now by equating eq.1 and eq.2You will geth=17/5 and k=-4/5Now find the radius by using distance formula i.e. radius=under root 180/25Now putting the values of h,k and radius in the equation of circle (x-h)^2+(y-k)^2=(radius)^2You will get the equation of circle as25x^2+25y^2-170x +40y +125=0
						
11 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 53 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 148 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details