 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Find the equation of the tangent of the circle x^2+y^2-2x-4y-4=0 which is perpendicular to the line 3x-4y+6=0

```
3 years ago

```							Line parallel to 3x-4y+6=0 is 3x-4y=cLet c be any constant.	A tangent have only one common point with circle.	Perpendicular distance of tangent from center of circle is equal radius.	Two tangent can be parallel.Here equation of circle will be(x-1)^2 +(y-2)^2 = 3^2.So center of circle is (1,2)Radius= 3So distance of 3x-4y-c= 0 from (1,2) is equal to 3.So,| (3–4*2-c)| /(3^2+4^2)^0.5 =3.=> so c= -20 ,10.So eqns will be3x-4y=10 and3x-4y=-20
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Analytical Geometry

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 53 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions