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Find the equation of the straight lines which pass through the origin and make an angle of 75° with the line x+y+√3(y-x)=a.
the slope of the given line = (√3–1)/(√3+1) =2-√3 or we can say that the given line makes an angle of 15° with the x-axis. Hence the y-axis or x=0 is a line that will make an angle of 75° with the given line and of course it passes through the origin. In addition, a line that has a slope of tan(120°)= -√3 will also make an angle of 75° with the given line and this line may be represented as: y=(-√3)x since it passes through the origin.
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