Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
A tangent to the parabola y^2=8x makes an angle 45° with the straight line y=3x +5. find eqn of tangent abd its point of contact ? A tangent to the parabola y^2=8x makes an angle 45° with the straight line y=3x +5. find eqn of tangent abd its point of contact ?
tan45 = |3 – m|/|1 + 3m| = 1/root2solvinf for m we get, m = ½.TANGENT OF parabola = > 2ydy/dx = 8dy/dx = 4/y1 |let x1 and y1 be the point of contact] m = 4/y1 = ½y1 = 8.x1 = 64/8 = 8the eqn. from point of contact (8,8) and slope = ½.(y – 8) = 0.5(x -8)y = x/2 + 4 is the required eqn.
Tan45=|3-m|/|1+3m|From this m=1/2,-2As we know that eqn of tangent of parabola is given by y=mx+a/m. .......1By putting value of m in eqn m We get x-2y+8=0 and 2x+y=0
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -