#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# A carbon compound contains 12.8% of carbon, 2.1% of hydrogen & 85.1% of bromine. The molecular weight of the compound is 187.9. Calculate the molecular formula of the compound? (Atomic weights:- H = 1.008, C = 12.0, B r= 79.9).

Siri
28 Points
4 years ago
C=12.8% at.wt. of C=12H=2.1%. at.wt. of H=1Be=85.1%. at.wt. of Br=80Now, 12.8/12 =1.067 2.1/1 = 2.1 85.1/80=1.067Dividing with 1.067 to get simple atomic ratio,1.067/1.067=12.1/1.067=21.067/1.067=1E.F= CH2BrE.F weight=12+(2×1)+80=94Molecular weight=187.9 (given)n=187.9/94= 2M.F= (E.F)×2 =(CH2Br)×2 =C2H4Br2
Siri
28 Points
4 years ago
C=12.8% at.wt. of C=12H=2.1%. at.wt. of H=1Be=85.1%. at.wt. of Br=80Now, 12.8/12 =1.067 2.1/1 = 2.1 85.1/80=1.067Dividing with 1.067 to get simple atomic ratio,1.067/1.067=12.1/1.067=21.067/1.067=1E.F= CH2BrE.F weight=12+(2×1)+80=94Molecular weight=187.9 (given)n=187.9/94= 2M.F= (E.F)×2 =(CH2Br)×2 =(C2H4Br2)
Siri
28 Points
4 years ago
C=12.8% at.wt. of C=12H=2.1%. at.wt. of H=1Be=85.1%. at.wt. of Br=80Now, 12.8/12 =1.067 2.1/1 = 2.1 85.1/80=1.067Dividing with 1.067 to get simple atomic ratio,1.067/1.067=12.1/1.067=21.067/1.067=1E.F= CH2BrE.F weight=12+(2×1)+80=94Molecular weight=187.9 (given)n=187.9/94= 2M.F= (E.F)×2 =(CH2Br)×2 =(C2H4Br2).
Charitha Gorrela
22 Points
4 years ago