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If P1 and P2 denotes the length of perpendiculars from the origin on the lines xsecb+ycosecb=2a (b=alpha) and xcosb+ysinb=acos2b respectively then (p1/p2,P2/P1) is equal to
Dear pallavi
use perpendicular distance formula
p1 =|2a|/√(sec2α + cosec2α)
= |2a|/√1/sin2α cos2α)
=|asin2α|
p2 =|acos2α|/√(sin2α +cos2α)
=|acos2α|
p1/p2 = tan2α
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