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# in a triangle abc if the product of sines of the angles of a triangle is P and if the product of cosines of a triangle is Q then the equation whose roots are tanA,tanB,tanC is? Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear sameer sai

given

sinA sinB sinC=p

cosA cosB cosC =q

so tanA tanB tanC =p/q

and A+B+C=180

use tan(a+b+c) formula

u will get  tanA+tanB+tanC=tanA tanB tanC

so        tanA+tanB+tanC=p/q

now

tanAtanB +tanB tanC+ tanC tanA=(sinA sinB cosC +sinB sinC cosA +sinC sinA cosB)/cosA cosB cosC

=1/q (sinA sinB cosC +sinC [sinB cosA + sinA cosB])

=1/q (sinA sinB cosC +sinC [sin(A+B)])

=1/q (sinA sinB cosC +sin2C )

=1/q (sinA sinB cosC +1-cos2C )

=1/q (1+cosC{-cosC+sinA sinB } )

=1/q (1+cosC cosA cosB  )

=1/q (1+q )

now  u can get equation.

qx3 -px2 +(1+q)x -p =0

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