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The length of the chord of the parabola y2=x which is bisected at the point (2,1) is?
a)51/2 b)4*31/2 c)3*31/2 d)2*51/2
T = S1
y-0.5(x+2) = 1^2 - 2 = -1
2y - x - 2 = -2
or, x = 2y
Put in the equation,
y^2 = 2y
or, y = 0 , 2
x = 0, 4
Points where the line cuts the parabola = (0,0), (4,2)
Length = sqrt(4^2 + 2^2) = sqrt(16+4) = sqrt(20) = 2*sqrt(5)
Option (d)
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