Sourabh Singh
Last Activity: 10 Years ago
hii
[(a)(b)(c)] = a.(bxc)
mod(a) mod(b) mod(c)sin(thetha)cos(alpha)
This value is given equal to
mod(a) mod(b) mod(c)
Hence sin(thetha)cos(alpha) = 1
thetha = pi/2
alpha = zero
hence b.c = 0 ; and a is parallel to the cross product hence perpendicular to b and c .
So option D is the correct answer