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Grade: 12
        a rectangular billiard table has vertices at  p(0,0), q(0,7) ,r(10,7)&s(10,0) . a small billiard ball starts at m(3,4) & moves in astraight line to the top of the table, bounces to the right of the table, then comes to rest at n(7,1) .what is the y-cordinate of the point where ball hits the right side of table?
7 years ago

Answers : (1)

AJIT AskiitiansExpert-IITD
68 Points
							

Dear ffggfg hkjj,

 

1953_21440_RRR.gif

I guess the above figure is what is meant by the question, We will apply the laws of reflection at the strike points of the ball. So the angle at which the ball is reflected after the first strike is equal to angle at which it had striked i.e A .

slopes:

PM : tan(90-A) = 3/x-3   or cot A =  3/x-3  -----------------------1

PQ: tan(-(90-A)) = y-7/10-x  or -Cot A = y-7/10-x-------------------2

QN: tan(90-A) = y-1/3 or cot A = y-1/3----------------------------3

divide 1 by 2 and 1 by 3

we get

10x-30 = xy-3y +21

x+ 9  = xy-3y +3

solving we get

x= 19/3 and y = 37/10

 

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

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Askiitians Expert

Ajit Singh Verma IITD

7 years ago
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