Aditya GuptaApproved Tutor Answer6 Years agow^3=1w^3 – 1= 0(w – 1)(w^2+w+1)= 0assuming w is not 1 itselfw^2+w+1= 0or w^2+w= – 1 now, let x= root w+ root w^2x^2 = w + w^2 + 2root(w^3)= – 1 + 2root(1)= 1so x= ± 1kindly approve :))
Arun6 Years agoDear student w^3 = 1 w^3 – 1 = 0(w – 1) (w^2 + 1 + w) = 0 hence w + w^2 = -1 only Hope it helps Regards