# value of [(2014^2-2020) (2014^2+4028-3) (2015)] / [(2011) (2013) (2016) (2017)], ()

Mimi Bhattacharya
13 Points
6 years ago
2014^2+4028-3
=2014^2+4028+1-4
={2014^2+(2×2014×1)+1^2}-4
=(2014+1)^2- 2^2
=(2014+1+2)(2014+1-2)
=2017×2013

2011×2016
=(2014-3)(2014+2)
=2014^2-(3+2)2014-(3×2)
=2014^2-2020

When we'll arrange the numerator and denominator, it'll be noticed that nearly all the numerator are cancelled and we're left with only 2015.
daksh
15 Points
4 years ago
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daksh
15 Points
4 years ago
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daksh
15 Points
4 years ago
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you must check it out
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