Two rays with common end points `O` forms a 30 degree angle. Point A lies on one ray, point B on the other ray and AB=1. The maximum possible length of OB is and options are (A) = root 3 (B) = 4/root 3 (C) = (root 3 +1)/root 2 (D) = 2

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Arun · Answer

Dear Meet Triangle OAB has the property that angle O = 30° and AB = 1 From sine law (sin A)/OB = (sin O)/AB (sin A)/OB = (1/2)/1 OB = 2 sinA Mazimum of sinA is 1 when A = 90°> Hence maximum of OB = 2 Option D is correct. Regards Arun (askIITians forum expert)

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Two rays with common end points `O` forms a 30 degree angle. Point A lies on one ray, point B on the other ray and AB=1. The maximum possible length of OB is and options are (A) = root 3 (B) = 4/root 3 (C) = (root 3 +1)/root 2 (D) = 2

Two rays with common end points `O` forms a 30 degree angle. Point A lies on one ray, point B on the other ray and AB=1. The maximum possible length of OB is and options are (A) = root 3 (B) = 4/root 3 (C) = (root 3 +1)/root 2 (D) = 2

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Two rays with common end points `O` forms a 30 degree angle. Point A lies on one ray, point B on the other ray and AB=1. The maximum possible length of OB is and options are (A) = root 3 (B) = 4/root 3 (C) = (root 3 +1)/root 2 (D) = 2

Two rays with common end points `O` forms a 30 degree angle. Point A lies on one ray, point B on the other ray and AB=1. The maximum possible length of OB is and options are (A) = root 3 (B) = 4/root 3 (C) = (root 3 +1)/root 2 (D) = 2

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