Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Three numbers are chosen at random from the set {0,1,2,....,29} without replacement. The probability that the sum of these numbers is 30 is: (a)5/812 (b)15/812 (c)5/406 (d)3/406

Three numbers are chosen at random from the set {0,1,2,....,29} without replacement. The probability that the sum of these numbers is 30 is:
(a)5/812
(b)15/812
(c)5/406
(d)3/406

Grade:12th pass

2 Answers

Harsh Patodia IIT Roorkee
askIITians Faculty 907 Points
6 years ago
Toatl possiblities 30C3
For sum 30
Start from first triad 0 1 29
Fix 0 and increase second number by 1 and decrease other by 1 till first number becomes 14 as after that repetion will start occuring
Total of 14 cases

Now increase 0 to 1 and fix it take second number 2 third 27
Again increase 2nd number by 1 and second number decrease by 1 till 2nd number become 14 and third becomes 15 after this repetition will occur
Total casses 13

Now start with triad 2 3 25
Make ensure you are taking second and third numbers greater then or equal to first to avoid repetition
In this total cases will be 11

You can proceed like this till first number number become 9 for that only case will be ther i.e. 9 10 11

You will get a total of 75 cases and you can find tthe required probability
Just follow this if you are unable to understand please repost.
Arif Ahmed
10 Points
6 years ago
Thank you!
Should have been able to do it myself.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free