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Grade: 11

                        

The sum of first 9 terms of the series 1³/1 +1³+2³/1+3...... Is

4 years ago

Answers : (2)

Anuj Shrivastav
32 Points
							
[hint: find the nth term and then find its summation]

Tn for the series is : Tn= {(n+1)^2 }/4

Then use the summation of this Tn with n from 1 to 9. 

∑ Tn = 96.

Hope this helps. 
Comment if you didn’t understand the above solution.
Anuj
4 years ago
A V Balaram
13 Points
							
Here
Tr= ((n+1))^2/4
that implies sum of nine digits will be 
 
= (1/4)(1^2+2^2+3^2--------10^2-1^2)
=96
one year ago
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