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Grade: 12th pass
        
The sum of 5 consecutive whole number is 2005.what is the sum of all the digits of these  5 numbers
3 years ago

Answers : (1)

Vikas TU
11142 Points
							
Given,
x + (x+1) + (x+2) + (x+3) + (x+4) =2005
5x + 10 = 2005
5x = 1995
x = 399
Numbers are therefore,
399, 400, 401, 402, 403
Now u can sum their digits.
3 years ago
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