Grade 9Algebra

The reminder when x^5 + kx^2 is divided by (x-1) (x-2) (x-3) contains no term in x^2. If teh value of k is -10a then a = ?
Ans = 9

ra

10 Years agoGrade 9

10 Years ago

on dividing x^5 + kx^2 with (x-1) (x-2) (x-3) we get the remainder (k+90)x²-239x+150

as the remainder contains no x² terms …............k+90=0............k= -90= -10(9)

first exp (x-1) (x-2) (x-3) and then solve the problem , on solving/dividing make sure that all the coefficients of x² are at same place.

i gave u remainder bcuz if u tried it u can solve 4 remainder

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