Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

The position vector r of a particle at time t is r = 2t2i + (t2 −4t)j + (3t−5)k. Find the velocity and the acceleration of the particle at time t. Show that when t = 2 5 the velocity and the acceleration are perpendicular to each other. The velocity and the acceleration are resolved into components along and perpendicular to the vector i−3j + 2k. Find the velocity and acceleration components parallel to this vector when t = 2 5.

5 months ago

Saurabh Koranglekar
3431 Points
Dear student

V = 4t, 2t-4, 3

A = 4, 2, 0

Here is assuming given expression for r = 2 t^2 i + (t^2 -4t)j + (3t-5)k
And t = 2 sec not 25

Kindly check and confirm

Regards

5 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions