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Grade: 12th pass
`         The position vector r of a particle at time t is r = 2t2i + (t2 −4t)j + (3t−5)k. Find the velocity and the acceleration of the particle at time t. Show that when t = 2 5 the velocity and the acceleration are perpendicular to each other. The velocity and the acceleration are resolved into components along and perpendicular to the vector i−3j + 2k. Find the velocity and acceleration components parallel to this vector when t = 2 5. `
one month ago

## Answers : (1)

Saurabh Koranglekar
askIITians Faculty
3138 Points
```							Dear studentV = 4t, 2t-4, 3A = 4, 2, 0Here is assuming given expression for r = 2 t^2 i + (t^2 -4t)j + (3t-5)kAnd t = 2 sec not 25Kindly check and confirmRegards
```
one month ago
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