Grade 12th PassAlgebra

the number of possible outcomes in a throw of n ordinary dice in which atlleast one of the dice shows an odd number is

demesaikiran

9 Years agoGrade 12th Pass

2 Answers

Harsh Patodia

9 Years ago

One dice out of n will have output 1,3,5 so three choices other dices will have 6 choices
So total will be 3.6.6.6.6.6.6. . . =3 x6^n-1

demesaikiran

9 Years ago

IT IS NOTHING BUT TOTAL NUMBER OF WAYS IN WHICH ALL THE NUMBERS WILL COME -NO DICE SHOWS AN ODD NUMBER(1,3,5)
SO TOTAL NUMBER OF EVEN NUMBERS ARE (2,4,6) HAS POSSIBILITIES TO OCCUR IS 3.3.3.3.3.3.3........N TIMES
HERE TOTAL NUMBER OF WAYS IN WHICH ALL NUMBERS WILL COME IS =6.6.6.6.6.6.6.........n TIMES
THERE FORE,REQUIRED ANSWER IS 6^n-3^n.