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the number of possible outcomes in a throw of n ordinary dice in which atlleast one of the dice shows an odd number is
One dice out of n will have output 1,3,5 so three choices other dices will have 6 choicesSo total will be 3.6.6.6.6.6.6. . . =3 x6n-1
IT IS NOTHING BUT TOTAL NUMBER OF WAYS IN WHICH ALL THE NUMBERS WILL COME -NO DICE SHOWS AN ODD NUMBER(1,3,5)SO TOTAL NUMBER OF EVEN NUMBERS ARE (2,4,6) HAS POSSIBILITIES TO OCCUR IS 3.3.3.3.3.3.3........N TIMES HERE TOTAL NUMBER OF WAYS IN WHICH ALL NUMBERS WILL COME IS =6.6.6.6.6.6.6.........n TIMES THERE FORE,REQUIRED ANSWER IS 6^n-3^n.
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