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Grade: 12th Pass

                        

the number of possible outcomes in a throw of n ordinary dice in which atlleast one of the dice shows an odd number is

4 years ago

Answers : (2)

Harsh Patodia
IIT Roorkee
askIITians Faculty
907 Points
							One dice out of n will have output 1,3,5 so three choices other dices will have 6 choices
So total will be 3.6.6.6.6.6.6. . . =3 x6n-1
4 years ago
demesaikiran
37 Points
							
IT IS NOTHING BUT TOTAL NUMBER OF WAYS IN WHICH ALL THE NUMBERS WILL COME -NO DICE SHOWS AN ODD NUMBER(1,3,5)
SO TOTAL NUMBER OF EVEN NUMBERS ARE (2,4,6) HAS POSSIBILITIES TO OCCUR IS 3.3.3.3.3.3.3........N TIMES 
HERE TOTAL NUMBER OF WAYS IN WHICH ALL NUMBERS WILL COME IS =6.6.6.6.6.6.6.........n TIMES 
THERE FORE,REQUIRED ANSWER IS 6^n-3^n.
4 years ago
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