The foot of the perpendicular drawn from the origin to the plane is (2,5,7). FInd the equation of the plane.

Hello student,
Please find the answer to your question below
Equation of plane passing through and perpendicular to oa
a=2i+5j+7k
n=OA=2i+5j+7k
Required plane equation is r.n=a.n
r(2i+5j+7k)=(2i+5j+7k)(2i+5j+7k)
so r(2i+5j+7k)=78
In cartesian form 2x+5y+7z=78
Note:the above notations r,n,oa are vectors