Grade 12Algebra

The area enclosed between the curve y = loge (x + e) and the coordinate axes is ?

sudhanshu

12 Years agoGrade 12

1 Answer

Jitender Singh

12 Years ago

Ans: 1

Area ‘A’:

$A = \int_{1-e}^{0}ln(x+e)dx$

$A = \int_{1-e}^{0}x^{0}ln(x+e)dx$

$A = (x.ln(x+e))_{1-e}^{0} -\int_{1-e}^{0} \frac{x}{x+e}dx$

$A = -\int_{1-e}^{0} \frac{x+e-e}{x+e}dx$

$A = \int_{1-e}^{0} (\frac{e}{x+e}-1)dx$

$A = (e.ln(x+e) -x)_{1-e}^{0} = 1$

Thanks & Regards

Jitender Singh

IIT Delhi

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The area enclosed between the curve y = loge (x + e) and the coordinate axes is ?

sudhanshu

1 Answer

Jitender Singh

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