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The AM between two positive numbers A and B (A>B) is twice the GM .prove that A:B= 2+√ 3 : 2-√3 The AM between two positive numbers A and B (A>B) is twice the GM .prove that A:B= 2+√ 3 : 2-√3
given condition is that(A+B)/2 = 2 =4Applying dividendo componendo It can be seen from nowSquare root both sidesComponents dividendo A/B =(1 +√ 3)/(-√ 3 +1)
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