Grade 12th passAlgebra
solve the following 2log3(x-3/x-7)+1= log3(x-3/x-1)
solve the following 2log3(x-3/x-7)+1= log3(x-3/x-1)
1 Answer
Shreya
2log3(x-3/x-7) + 1= log3(x-3/x-1)
Sol. log3(x-3/x-7)2 - log3(x-3/x-1) = -1
log3{(x-3)(x-1)/(x-7)2}= -1
Now we get,
3-1={(x-3)(x-1)/(x-7)2}
1/3= x2-4x+3/x2-14x+49
3x2-12x+9= x2-14x+49
2x2+2x-40=0
x2+x-20=0
(x+5)(x-4)=0
x= -5 or 4(rejected as the log doesn't accept negative numbers.)
Ans is x=-5
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