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Grade: 11

                        

sir n cube greater than =n. what is the relation

6 years ago

Answers : (1)

Mohan Chandar
39 Points
							We shall prove it by math Induction...
 
When n=1, n^3=1^3=1=n...

Let K^3 >= k... we shall prove that (K+1)^3 >= k+1...

(k+1)^3 = K^3 + 1 + 3k^2 + 3k
              >= K + 3(k+1) + 1
              >= 3(k+1) + k+1
              >= 4(k+1)
              >= k+1.......

Hence proved....
						
6 years ago
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