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Grade: 12th pass
        
 simpilify : 1+(3+1)(3^2+1)(3^4+1)(3^16+1)(3^32+1)(3^64+1)=?
one year ago

Answers : (1)

Aditya Gupta
1807 Points
							
let x=(3+1)(3^2+1)(3^4+1)(3^16+1)(3^32+1)(3^64+1)
x*(3-1)=(3-1)*(3+1)(3^2+1)(3^4+1)(3^16+1)(3^32+1)(3^64+1)
=(3^2-1)*(3^2+1)(3^4+1)(3^16+1)(3^32+1)(3^64+1)
=(3^4-1)*(3^4+1)(3^16+1)(3^32+1)(3^64+1)
........
=3^128-1
or, x+1= 3^128
one year ago
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