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`        Q.47 see image.........................................................`
9 months ago

1934 Points
```							r1= K/(s – h) and R= abh/4K where K is area and R is circumradius and r1 is exradius. obviously K= ab/2. so that R= h/2so ratio R/r1= h(s – h)/2K= h(s – h)/ab= root2/(root2 + root3)now, let a/b= x and by pythagoras a^2+b^2= h^2 or h= b*root(1+x^2)also, 2s= a+b+hso you can plug in these values in terms of x and you shall get the ratio. finding angles B and C is easy as tan B and tanC can be found out once the value of x is known.kindly approve :)
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7 months ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions