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`        Please answer in detail……...................:.:.:.:.:.:.'..:.:.:.'.:..:.:.:.:.:.:.:..:.:.:.:.:.:.:..:.:.:.:.:`
one year ago

Arun
23345 Points
```							 Since The QE has no distinct roots, so b^2 = 24aOr, 3a = b^2 / 8 So 3a+b = b + b^2/8 =(8b+b^2)/8 = {(b+4)^2 - 16}/8 = (b+4)^2/8 - 2.The minimum value of this will clearly be -2 -------------(when b = -4 and 3a = 2, or a=2/3) That solves the Problem.
```
one year ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions