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Grade: 11
        
Please answer in detail……...................:.:.:.:.:.:.'..:.:.:.'.:..:.:.:.:.:.:.:..:.:.:.:.:.:.:..:.:.:.:.:
5 months ago

Answers : (1)

Arun
19766 Points
							
 

Since The QE has no distinct roots, so b^2 = 24a

Or, 3a = b^2 / 8

 

So 3a+b = b + b^2/8 =(8b+b^2)/8 = {(b+4)^2 - 16}/8 = (b+4)^2/8 - 2.

The minimum value of this will clearly be -2 -------------(when b = -4 and 3a = 2, or a=2/3)

 

That solves the Problem.

 
 
5 months ago
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