0

Guest

Courses New

para. Q.23-25 see image.................................................

para. Q.23-25 see image.................................................

Question Image
Grade:12

1 Answers

Aditya Gupta
2081 Points
4 years ago
C= (A+B)^-1*(A-B)
pre multiplying by A+B on both sides
(A+B)C= A – B
also, we can take transpose both sides and get trans((A+B)C)= trans(A – B)
CT(A+B)T= AT – BT
or CT(AT+BT)= AT – BT 
A is symmetric so AT= A and BT= – B because B is skew symmetric.
so CT(A – B)= A+B
now CT(A+B)C= CT(A – B)
= A+B
similarly CT(A – B)C= (A+B)C= A – B
now add both the results,
CT(A+B)C + CT(A – B)C= 2A
CT[(A+B)C + (A – B)C]= 2A
CT[(A+B) + (A – B)]C= 2A
CT[2A]C= 2A
or CTAC= A
kindly ask only one ques per thread.
KINDLY APPROVE :)

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More